Don't double insert widget. Props mdawaffe. fixes #6191
git-svn-id: https://develop.svn.wordpress.org/trunk@7267 602fd350-edb4-49c9-b593-d223f7449a82
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@ -104,8 +104,8 @@ jQuery(function($) {
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$('a.widget-control-remove', context).click( function() {
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var w = $(this).parents('li:first').find('input[@name^="widget-id"]').val();
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$(this).parents('li:first').remove();
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var t = $('#widget-list ul#widget-control-info-' + w + ' textarea');
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t.parent().html( t.text() ).parents('li.widget-list-item:first').children( 'h4' ).children('a.widget-action')
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var t = $('#widget-list ul#widget-control-info-' + w + ' textarea'); // will be empty for multi-widgets
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t.parents('.widget-control-info:first').html( t.text() ).parents('li.widget-list-item:first').children( 'h4' ).children('a.widget-action')
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.show().text( widgetsL10n.add ).unbind().click( addClick );
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var n = parseInt( $('#widget-count').text(), 10 ) - 1;
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$('#widget-count').text( n.toString() )
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