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NSH: if # appears on line, need to comment ignore additinal commands on the line

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This commit is contained in:
Gregory Nutt 2014-07-01 13:43:40 -06:00
parent 44ea3903f9
commit 58424404f0
1 changed files with 10 additions and 9 deletions
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19
nshlib/nsh_parse.c
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@ -196,7 +196,7 @@ static int nsh_parse_command(FAR struct nsh_vtbl_s *vtbl, FAR char *cmdline);
static const char g_token_separator[] = " \t\n";
#ifndef NSH_DISABLE_SEMICOLON
static const char g_line_separator[] = "\";\n";
static const char g_line_separator[] = "\"#;\n";
#endif
#ifdef CONFIG_NSH_ARGCAT
static const char g_arg_separator[] = "`$";
@ -2191,22 +2191,23 @@ int nsh_parse(FAR struct nsh_vtbl_s *vtbl, FAR char *cmdline)
np->np_loffs = (uint16_t)(working - cmdline);
#endif
/* A command may be terminated with a newline character, the end of the
* line, or a semicolon. NOTE that the set of delimiting characters
* includes the quotation mark. We need to handle quotation marks here
* because a semicolon or newline character within a quoted string must
* be ignored.
* line, a semicolon, or a '#' character. NOTE that the set of
* delimiting characters includes the quotation mark. We need to
* handle quotation marks here because any other delimiter within a
* quoted string must be treated as normal text.
*/
len = strcspn(working, g_line_separator);
ptr = working + len;
/* Check for the last command on the line. This means that the none
* of the delimiting characters was found or that the newline character
* was found. Anything after the newline character is ignored (there
* should not be anything.
* of the delimiting characters was found or that the newline or '#'
* character was found. Anything after the newline or '#' character
* is ignored (there should not be anything after a newline, of
* course).
*/
if (*ptr == '\0' || *ptr == '\n')
if (*ptr == '\0' || *ptr == '\n' || *ptr == '#')
{
/* Parse the last command on the line */