quickjs/Makefile: pass jobserver status to submake
N/A Use +make or $(MAKE) instead of make -C Signed-off-by: Peter Bee <bijunda1@xiaomi.com>
This commit is contained in:
parent
6895da98e3
commit
a3ccf59204
@ -78,13 +78,13 @@ $(QUICKJS_UNPACK)/.patch: $(QUICKJS_UNPACK)
|
||||
$(Q) touch $(QUICKJS_UNPACK)/.patch
|
||||
|
||||
build_host: $(QUICKJS_UNPACK)/.patch
|
||||
make -C $(QUICKJS_UNPACK) \
|
||||
$(MAKE) -C $(QUICKJS_UNPACK) \
|
||||
CONFIG_BIGNUM=$(CONFIG_INTERPRETERS_QUICKJS_BIGNUM)
|
||||
|
||||
context:: build_host
|
||||
|
||||
clean::
|
||||
$(Q) test ! -d $(QUICKJS_UNPACK) || make -C $(QUICKJS_UNPACK) clean
|
||||
$(Q) test ! -d $(QUICKJS_UNPACK) || $(MAKE) -C $(QUICKJS_UNPACK) clean
|
||||
|
||||
distclean::
|
||||
$(call DELDIR, $(QUICKJS_UNPACK))
|
||||
|
Loading…
Reference in New Issue
Block a user