/**************************************************************************** * mm/mm_heap/mm_memalign.c * * Licensed to the Apache Software Foundation (ASF) under one or more * contributor license agreements. See the NOTICE file distributed with * this work for additional information regarding copyright ownership. The * ASF licenses this file to you under the Apache License, Version 2.0 (the * "License"); you may not use this file except in compliance with the * License. You may obtain a copy of the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, WITHOUT * WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the * License for the specific language governing permissions and limitations * under the License. * ****************************************************************************/ /**************************************************************************** * Included Files ****************************************************************************/ #include #include #include #include "mm_heap/mm.h" /**************************************************************************** * Public Functions ****************************************************************************/ /**************************************************************************** * Name: mm_memalign * * Description: * memalign requests more than enough space from malloc, finds a region * within that chunk that meets the alignment request and then frees any * leading or trailing space. * * The alignment argument must be a power of two (not checked). 8-byte * alignment is guaranteed by normal malloc calls. * ****************************************************************************/ FAR void *mm_memalign(FAR struct mm_heap_s *heap, size_t alignment, size_t size) { FAR struct mm_allocnode_s *node; size_t rawchunk; size_t alignedchunk; size_t mask = (size_t)(alignment - 1); size_t allocsize; /* If this requested alinement's less than or equal to the natural * alignment of malloc, then just let malloc do the work. */ if (alignment <= MM_MIN_CHUNK) { return mm_malloc(heap, size); } /* Adjust the size to account for (1) the size of the allocated node, (2) * to make sure that it is an even multiple of our granule size, and to * include the alignment amount. * * Notice that we increase the allocation size by twice the requested * alignment. We do this so that there will be at least two valid * alignment points within the allocated memory. * * NOTE: These are sizes given to malloc and not chunk sizes. They do * not include SIZEOF_MM_ALLOCNODE. */ size = MM_ALIGN_UP(size); /* Make multiples of our granule size */ allocsize = size + 2*alignment; /* Add double full alignment size */ /* Then malloc that size */ rawchunk = (size_t)mm_malloc(heap, allocsize); if (rawchunk == 0) { return NULL; } /* We need to hold the MM semaphore while we muck with the chunks and * nodelist. */ mm_takesemaphore(heap); /* Get the node associated with the allocation and the next node after * the allocation. */ node = (FAR struct mm_allocnode_s *)(rawchunk - SIZEOF_MM_ALLOCNODE); /* Find the aligned subregion */ alignedchunk = (rawchunk + mask) & ~mask; /* Check if there is free space at the beginning of the aligned chunk */ if (alignedchunk != rawchunk) { FAR struct mm_allocnode_s *newnode; FAR struct mm_allocnode_s *next; size_t precedingsize; /* Get the node the next node after the allocation. */ next = (FAR struct mm_allocnode_s *)((FAR char *)node + node->size); /* Make sure that there is space to convert the preceding * mm_allocnode_s into an mm_freenode_s. * I think that this should always be true */ DEBUGASSERT(alignedchunk >= rawchunk + 8); newnode = (FAR struct mm_allocnode_s *) (alignedchunk - SIZEOF_MM_ALLOCNODE); /* Preceding size is full size of the new 'node,' including * SIZEOF_MM_ALLOCNODE */ precedingsize = (size_t)newnode - (size_t)node; /* If we were unlucky, then the alignedchunk can lie in such a position * that precedingsize < SIZEOF_NODE_FREENODE. We can't let that happen * because we are going to cast 'node' to struct mm_freenode_s below. * This is why we allocated memory large enough to support two * alignment points. In this case, we will simply use the second * alignment point. */ if (precedingsize < SIZEOF_MM_FREENODE) { alignedchunk += alignment; newnode = (FAR struct mm_allocnode_s *) (alignedchunk - SIZEOF_MM_ALLOCNODE); precedingsize = (size_t)newnode - (size_t)node; } /* Set up the size of the new node */ newnode->size = (size_t)next - (size_t)newnode; newnode->preceding = precedingsize | MM_ALLOC_BIT; /* Reduce the size of the original chunk and mark it not allocated, */ node->size = precedingsize; node->preceding &= ~MM_ALLOC_BIT; /* Fix the preceding size of the next node */ next->preceding = newnode->size | (next->preceding & MM_ALLOC_BIT); /* Convert the newnode chunk size back into malloc-compatible size by * subtracting the header size SIZEOF_MM_ALLOCNODE. */ allocsize = newnode->size - SIZEOF_MM_ALLOCNODE; /* Add the original, newly freed node to the free nodelist */ mm_addfreechunk(heap, (FAR struct mm_freenode_s *)node); /* Replace the original node with the newlay realloaced, * aligned node */ node = newnode; } /* Check if there is free space at the end of the aligned chunk. Convert * malloc-compatible chunk size to include SIZEOF_MM_ALLOCNODE as needed * for mm_shrinkchunk. */ size = MM_ALIGN_UP(size + SIZEOF_MM_ALLOCNODE); if (allocsize > size) { /* Shrink the chunk by that much -- remember, mm_shrinkchunk wants * internal chunk sizes that include SIZEOF_MM_ALLOCNODE. */ mm_shrinkchunk(heap, node, size); } mm_givesemaphore(heap); return (FAR void *)alignedchunk; }