/**************************************************************************** * libs/libc/math/lib_sqrtf.c * * This file is a part of NuttX: * * Copyright (C) 2012 Gregory Nutt. All rights reserved. * Ported by: Darcy Gong * * It derives from the Rhombus OS math library by Nick Johnson which has * a compatibile, MIT-style license: * * Copyright (C) 2009-2011 Nick Johnson * * Permission to use, copy, modify, and distribute this software for any * purpose with or without fee is hereby granted, provided that the above * copyright notice and this permission notice appear in all copies. * * THE SOFTWARE IS PROVIDED "AS IS" AND THE AUTHOR DISCLAIMS ALL WARRANTIES * WITH REGARD TO THIS SOFTWARE INCLUDING ALL IMPLIED WARRANTIES OF * MERCHANTABILITY AND FITNESS. IN NO EVENT SHALL THE AUTHOR BE LIABLE FOR * ANY SPECIAL, DIRECT, INDIRECT, OR CONSEQUENTIAL DAMAGES OR ANY DAMAGES * WHATSOEVER RESULTING FROM LOSS OF USE, DATA OR PROFITS, WHETHER IN AN * ACTION OF CONTRACT, NEGLIGENCE OR OTHER TORTIOUS ACTION, ARISING OUT OF * OR IN CONNECTION WITH THE USE OR PERFORMANCE OF THIS SOFTWARE. * ****************************************************************************/ /**************************************************************************** * Included Files ****************************************************************************/ #include #include #include #include #include "libc.h" /**************************************************************************** * Public Functions ****************************************************************************/ #ifndef CONFIG_LIBM_ARCH_SQRTF float sqrtf(float x) { float y; /* Filter out invalid/trivial inputs */ if (x < 0.0F) { set_errno(EDOM); return NAN_F; } if (isnan(x)) { return NAN_F; } if (isinf_f(x)) { return INFINITY_F; } if (x == 0.0F) { return 0.0F; } /* Guess square root (using bit manipulation) */ y = lib_sqrtapprox(x); /* Perform three iterations of approximation. This number (3) is * definitely optimal */ y = 0.5F * (y + x / y); y = 0.5F * (y + x / y); y = 0.5F * (y + x / y); return y; } #endif