8e32a3ce24
The original assumption was that the interrupt numbers are divided so that 16 pins from 1 port are handled by a single interrupt source. So source 0 would handle pins 0-15 and source 1 would handle pins 16-31. This assumption is wrong, each pin has two sources, thus there are two interrupt lines for each pin. The driver uses source 0, and leaves source 1 disabled. |
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a64 | ||
fvp-v8r | ||
goldfish | ||
imx8 | ||
imx9 | ||
qemu | ||
rk3399 | ||
.gitignore | ||
arch.h | ||
elf.h | ||
inttypes.h | ||
irq.h | ||
limits.h | ||
setjmp.h | ||
spinlock.h | ||
stdarg.h | ||
syscall.h | ||
types.h |