nuttx/libs/libnx/nxglib/nxglib_rectoverlap.c
Alin Jerpelea 88fa869a04 libnx: Author Gregory Nutt: update licenses to Apache
Gregory Nutt has submitted the SGA and we can migrate the licenses
 to Apache.

Signed-off-by: Alin Jerpelea <alin.jerpelea@sony.com>
2021-02-25 01:44:30 -08:00

55 lines
2.2 KiB
C

/****************************************************************************
* libs/libnx/nxglib/nxglib_nulloverlap.c
*
* Licensed to the Apache Software Foundation (ASF) under one or more
* contributor license agreements. See the NOTICE file distributed with
* this work for additional information regarding copyright ownership. The
* ASF licenses this file to you under the Apache License, Version 2.0 (the
* "License"); you may not use this file except in compliance with the
* License. You may obtain a copy of the License at
*
* http://www.apache.org/licenses/LICENSE-2.0
*
* Unless required by applicable law or agreed to in writing, software
* distributed under the License is distributed on an "AS IS" BASIS, WITHOUT
* WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the
* License for the specific language governing permissions and limitations
* under the License.
*
****************************************************************************/
/****************************************************************************
* Included Files
****************************************************************************/
#include <nuttx/config.h>
#include <stdbool.h>
#include <nuttx/nx/nxglib.h>
/****************************************************************************
* Public Functions
****************************************************************************/
/****************************************************************************
* Name: nxgl_rectoverlap
*
* Description:
* Return true if the two rectangles overlap
*
****************************************************************************/
bool nxgl_rectoverlap(FAR struct nxgl_rect_s *rect1,
FAR struct nxgl_rect_s *rect2)
{
/* The neither is wholly above, below, right, or left of the other, then
* the two rectangles overlap in some fashion.
*/
return (rect1->pt1.x <= rect2->pt2.x) && /* false: rect1 is wholly to the right */
(rect2->pt1.x <= rect1->pt2.x) && /* false: rect2 is wholly to the right */
(rect1->pt1.y <= rect2->pt2.y) && /* false: rect1 is wholly below rect2 */
(rect2->pt1.y <= rect1->pt2.y); /* false: rect2 is wholly below rect1 */
}