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The original assumption was that the interrupt numbers are divided so that 16 pins from 1 port are handled by a single interrupt source. So source 0 would handle pins 0-15 and source 1 would handle pins 16-31. This assumption is wrong, each pin has two sources, thus there are two interrupt lines for each pin. The driver uses source 0, and leaves source 1 disabled. |
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| .. | ||
| chip.h | ||
| imx93_irq.h | ||
| irq.h | ||